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Ionic Bond

Anhydrous A...

Question

Anhydrous $A l C l_{3}$ is a covalent compound. From the data given below, predict whether it would remain covalent or become ionic in an aqueous solution.
(Ionisation energy of $A L = 5137 {K J m o l}^{- 1}$ )
$Δ H$ hydration for ${A l}^{3 +} = - 4665 K J {m o l}^{- 1}$
$Δ H$ hydration for ${C l}^{-} = - 381 K J {m o l}^{- 1}$

A

Ionic

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B

Covalent

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C

Partially ionic

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D

Partially covalent

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Solution

The correct option is A Ionic
We have that ${A l C l}_{3} +$ Aqueous $= {A l C l}_{3} (a q)$
$Δ H =$ Energy liberated during hydration $+$ Energy used during ionisation
$= - 4665 - (3 \times 381) + 5137 = - 671$
Here, $Δ H > Δ_{i o n i s a t i o n}$ .
$∴$ Aqueous solution of ${A l C l}_{3}$ is ionic.

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Similar questions

A l C l_{3}

is covalent from the data given below predict whether it would remain covalent or become ionic in aqueous solution.

Ionization energy for A l C l_{3} = 5137 k J m o l^{- 1}

Δ H_{hydration}

A l^{+ 3} i s - 4665 k J m o l^{- 1}

Δ H_{hydration}

C l^{-}

k J m o l^{- 1}

A l {C l}_{3}

is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution.

Given : Ionization energy for

A l {C l}_{3} = 5137

^{- 1}

Δ_{H y d r a t i o n}

{A l}^{3 +} = - 4665

^{- 1}

Δ_{H y d r a t i o n}

{C l}^{-} = - 381

^{- 1}

A l C l_{3}

is covalent from the data given below predict whether it would remain covalent or ionic in aqueous solution.

Ionization energy for A l C l_{3} = 5137 k J m o l^{- 1}

Δ H_{hydration}

A l^{+ 3} = - 4665 k J m o l^{- 1}

Δ H_{hydration}

C l^{-}

k J m o l^{- 1}

Q. Ionisation energy of

A l t o A l^{3 +} = 5137 k J m o l^{- 1} △ H_{h y d r a t i o n} o f : A l^{3 +} = - 4665 k J m o l^{- 1} a n d f o r C l^{-} = - 381 k J m o l^{- 1} .

Which of the following statement is correct?

A l C l_{3}

is covalent. from the data given below
Lattice Energy

= 5137 K J m o l^{- 1}

△ H h y d r a t i o n A l^{3 +} = - 4665 K J / m o l^{- 1}

△ H h y d r a t i o n C l^{-} = - 381 K J / m o l^{- 1}

Identify the correct statement-

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