Question

Aniline when acetylated, the product on nitration followed by alkaline hydrolysis gives:

• A. o-Nitroacetanilide
• B. p-Nitroaniline
• C. m-Nitroaniline
• D. Acetanilide

Answer 1

The correct option is B p-Nitroaniline

Acetanilide on nitration followed by alkaline hydrolysis :

It occurs under the presence of $H_{2}S{O}_4$ and $HN{O}_3$

Aniline is highly, ring activating so it forms both o- and p- products. But, on acetylation of $N{H}_2$forms acetanilide that deactivates the N as it diverts the lone pair in through cross conjugation.

Thus, we get p-nitroaniline.

Option B is correct.