Anita invested some money at 8% and Rs.400 more than that amount at 9%. The yearly interest from the two investments was Rs.87. How much did Anita invest at each rate?
A
Anita invested Rs.300 at 8%
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B
Anita invested Rs.700 at 9%
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C
Anita invested Rs.700 at 8%
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D
Anita invested Rs.300 at 9%
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Solution
The correct options are B Anita invested Rs.300 at 8% D Anita invested Rs.700 at 9% Let x represent the amount Anita invested at 8% and let y represent the amount the invested at 9%. The amount invested at 9% was Rs. 400 more than at 8%.
Hence, y=x+400 The yearly interest from the two investments was Rs. 87.
Hence, 0.08x+0.09y=87 From the first equation we can substitute x+400 for y in the second equation and solve for x. 0.08x+0.09(x+400)=87 8x+9(x+400)=8700 8x+9x+3600=8700 17x=5100 x=300 Therefore, Anita invested Rs. 300 at 8% and she invested 300+400=Rs.700 at 9%.