Ankit is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Ankit is able to pull the block to a total distance of 6.5 m. Find net work done.
78 J
Force applied by Ankit, F1=22 N
Force applied by Gopal, F2=10 N
Since, greater force is applied in Ankit's direction, net force will be acting in that direction.
∴ Net force =22−10=12 N
Given: Total displacement =6.5 m
Net work done = Net force × total displacement =12×6.5=78 J
Therefore, net work done is 78 J.