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Question

# Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in the opposite direction. The block moves a distance of 6.5 m in the same direction in which Vijay is pulling it. The work done on the block is:

A

12 J

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B

90 J

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C

85 J

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D

78 J

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Solution

## The correct option is D 78 J Given: Force applied by Vijay, F1=22 N Force applied by Gopal, F2=10 N. Displacement, s=6.5 m Since, both the forces are acting in the opposite directions, net force is given by: F=F1−F2 F=22−10=12 N The work done on the block is given by the product of displacement and the net force applied on it. Hence it is given by: W=F×s W=12×6.5=78 J

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