Ankit is pulling a block with $22 N$ force and Gopal is pulling it with $10 N$ force in opposite direction. Ankit is able to pull the block to a total distance of $6.5 m .$ Find net work done.

$12 J$

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$90 J$

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$85 J$

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$78 J$

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Solution

The correct option is D
$78 J$

Force applied by Ankit, $F_{1} = 22 N$

Force applied by Gopal, $F_{2} = 10 N$

Since, greater force is applied in Ankit's direction, net force will be acting in that direction.

$∴$ Net force $= 22 - 10 = 12 N$

Given: Total displacement $= 6.5 m$

Net work done $=$ Net force $\times$ total displacement $= 12 \times 6.5 = 78 J$

Therefore, net work done is 78 J.

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