Question

Answer the following question:

The gas produces dense white fumes with Ammonia gas.

Answer 1

Hydrogen chloride gas$\left(\mathrm{HCl}\right)$ produces dense white fumes with Ammonia gas$\left({\mathrm{NH}}_3\right)$.

$$\begin{gathered} {\mathrm{NH}}_3\left(\mathrm{g}\right)+\mathrm{HCl}\left(\mathrm{g}\right)\to {\mathrm{NH}}_4\mathrm{Cl}\left(\mathrm{s}\right) \\ \left(\mathrm{ammonia}\right)(\mathrm{hydrochloric}(\mathrm{ammonium} \\ \mathrm{acid})\mathrm{chloride}) \end{gathered}$$

• Here in this reaction, when $\left({\mathrm{NH}}_3\right)$ammonia gas reacts with $\left(\mathrm{HCl}\right)$ hydrochloric gas to produce ammonium chloride with dense white fumes.
• This can also be used as a test to detect the presence of ammonia gas.

Hence, the gas that produces dense white fumes with ammonia gas is hydrochloric gas$\left(\mathrm{HCl}\right)$.