Question

Answer the following questions
A current of $1.50A$ was passed through an electrolytic cell containing $AgN{O}_3$ solution with inert electrodes . The weight of $Ag$ deposited was $1.50g$ . How long did the current flow ?

Answer 1

$A{g}^{+}{e}^{-}\to Ag$
Quantity of charge required to deposit $108g$ of silver $=96500C$
$\therefore$ Quantity of charge required to deposit $1.50g$ of silver = $\frac{96500}{108}\times 1.50=1340.28C$
$t=\frac{Q}{I}$
$\therefore$ Time taken $=\frac{1340.28}{1.50}=893.52s$