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Question

Answer the following questions: (a) The angle subtended at the eye by an object is equal to the angle subtended at the eye by the virtual image produced by a magnifying glass. In what sense then does a magnifying glass provide angular magnification? (b) In viewing through a magnifying glass, one usually positions one’s eyes very close to the lens. Does angular magnification change if the eye is moved back? (c) Magnifying power of a simple microscope is inversely proportional to the focal length of the lens. What then stops us from using a convex lens of smaller and smaller focal length and achieving greater and greater magnifying power? (d) Why must both the objective and the eyepiece of a compound microscope have short focal lengths? (e) When viewing through a compound microscope, our eyes should be positioned not on the eyepiece but a short distance away from it for best viewing. Why? How much should be that short distance between the eye and eyepiece?

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Solution

a)

Even though the size of the virtual image that is produced by a magnifying glass is bigger than the actual object, the angular size of the image is equal to the angular size of the object. A magnifying glass helps to see the objects placed closer than the least distance of distinct vision ( 25cm ). The closer the object is to the eye, the larger is its angular size. A magnifying glass provides angular magnification. With magnification, the object can be placed much closer to the eye.

b)

When the distance between the eye and a magnifying glass is increased, the angle subtended at the eye by the object becomes slightly less than the angle subtended by it at the lens. So, the angular magnification decreases a little. Image distance does not have any effect on angular magnification.

c)

The focal length of a convex lens cannot be decreased by a great amount to increase the magnifying power. This is because making lenses with very small focal lengths is a complex task. Moreover, the convex lenses having small focal length produce spherical and chromatic aberrations.

d)

The angular magnification produced by the eyepiece of a compound microscope is given as,

α e =[ ( 25 f e )+1 ]

Where, f e is the focal length of the eyepiece.

Thus, the smaller the focal length of the eyepiece, the greater the magnification produced.

The angular magnification produced by the objective of a compound microscope is given as,

α o = 1 ( | u 0 | f 0 )

Where, u 0 is the object distance for the objective lens and f 0 is focal length of the objective lens.

Thus, the smaller the focal length of the objective, the greater the magnification produced.

The magnification is large when u o > f o . In the case of a microscope, the object is kept closer to the objective lens. Hence, the object distance is very little. Since u o is small, f o will be even smaller. Therefore, f e and f o are both small in the given condition.

e)

We are unable to collect much refracted light when we place our eyes very close to the eyepiece of a compound microscope. As a result, there is substantial decrement in the field of view. Hence, the clarity of the image gets blurred. The eye-ring attached to the eyepiece gives the best position for viewing through a compound microscope. The precise location of the eye depends on the separation between the objective lens and the eyepiece.

Thus, when viewing through a compound microscope, our eyes should be positioned not on the eyepiece but a short distance away from it for best viewing.


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