Question

Answer the following questions for Zn atom:
How many electrons have $l-m$=$1$?

Answer 1

electronic configuration of Zn is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^2$

Case $1:n=2l=1,m=0$ means $\left[2p\right]$ which have 6 electrons.

Case $2:n=3,l=1,m=0$ means $\left[3p\right]$ which have 6 electrons.

Case $1:n=3,l=2,m=1$ means $\left[3d\right]$ which have 10 electrons.

So total number of electron having $[l-m=1]$ is $6+6+10=22$