Question

$AOBC$ is a quadrant of a circle of radius $10m$. Calculate the area of the shaded portion.

Answer 1

Area of shaded part $=$ Area of quadrant $-$ Area of triangle

$=\frac{\pi r^2}{4}-\frac{1}{2}bh$

$=\frac{\pi \times {10}^2}{4}-\frac{1}{2}\times 10\times 10$

$=25\pi -50$

$=28.54m^2.$

Hence, the answer is $28.54m^2.$