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Molarity

Approximate ...

Question

Approximate $p H$ of $0.01 M N a H A$ is calculated by ? $(K_{a_{1}} = 10^{- 6}$ and $K_{a_{2}} = 10^{- 8}$ are ionization constants of $H_{2} A)$

A

p H = 7 + \frac{p K_{a_{1}}}{2} + \frac{log C}{2}

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B

p H = 7 - \frac{p K_{a_{1}}}{2} - \frac{log C}{2}

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C

p H = \frac{p K_{a_{1}} + p K_{a_{2}}}{2}

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D

None of these

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Solution

The correct option is C $p H = \frac{p K_{a_{1}} + p K_{a_{2}}}{2}$

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