Question

Area bounded by $y=\sqrt{a^2-x^2},x+y=0$ and $y$-axis in sq. units is:

• A. $a^2(\frac{\pi }{2})$
• B. $a^2(\frac{\pi }{4})$
• C. $a^2(\frac{\pi }{8})$
• D. $a^2\pi$

Answer 1

Answer: (C)

$a^2(\frac{\pi }{8})$

$y=\sqrt{a^2-x^2},x+y=0$
its 1/8 of the segment of the circle So, the area is $\frac{\pi a^2}{8}$