Question

Area of a sector of a circle, with radius 6 cm, is $\frac{132}{m}c{m}^2$. If angle of the sector is ${60}^{\circ }$, $m$ is equal to

Answer 1

Area of sector = $\frac{\theta }{{360}^{\circ }}\pi r^2=\frac{60}{360}\times \frac{22}{7}\times r^2$
Thus area = $\frac{60}{360}\times \frac{22}{7}\times 6^2=\frac{132}{7}c{m}^2$

It is given equal to $\frac{132}{m}c{m}^2$

Thus, $m=7$.