Question

Area of the triangle ABC a=2, b= 5, $\angle C=60$ in sq. units is

• A. $14/\sqrt{6}$
• B. $2/\sqrt{6}$
• C. $3/\sqrt{6}$
• D. none

Answer 1

The correct option is D none

Area=$△=\frac{1}{2}\ast base\ast height$

Height $=5sin{60}^o=\frac{5\sqrt{3}}{2}$

Base $=2$

$△=\frac{1}{2}\ast \frac{5\sqrt{3}}{2}\ast 2=\frac{5\sqrt{3}}{2}$

Therefore, Answer is $D$