Question

Question 75.
Arrange 12.142, 12.124, 12.104, 12.401 and 12.214 in ascending order.

Answer 1

Given numbers are 12.142, 12.124, 12.104, 12.401 and 12.214.
$\therefore$ 12.142 = 10+2+$\frac{1}{10}$+$\frac{4}{100}$+$\frac{2}{1000}$
12.124 = 10+2+$\frac{1}{10}$+$\frac{2}{100}$+$\frac{4}{1000}$
12.104 = 10+2+$\frac{1}{10}$+$\frac{0}{100}$+$\frac{4}{1000}$
12.401 = 10+2+$\frac{4}{10}$+$\frac{0}{100}$+$\frac{1}{1000}$
12.214 = 10+2+$\frac{2}{10}$+$\frac{1}{100}$+$\frac{2}{1000}$
Here, whole part of all numbers are same and tenths part of 12.142, 12.124 and 12.104 are same.
Now, tenths part of 12.401 = $\frac{4}{10}$
and tenths part of 12.214 = $\frac{2}{10}$
$\because$ $\frac{4}{10}$>$\frac{2}{10}$
$\therefore$ 12.401>12.214
Again, hundredths part of 12.142 = $\frac{4}{100}$
$\therefore$ Hundredths part of 12.124 = $\frac{2}{100}$
and hundredths part of 12.104 = $\frac{0}{100}$
$\because$ $\frac{4}{100}$>$\frac{2}{100}$>$\frac{0}{100}$
$\therefore$ 12.142 > 12.124 > 12.104
Hence, the ascending order of given number are
12.104 < 12.124 < 12.142 <12.214 < 12.401.