Arrange $B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2} a n d B a C l_{2}$ according to their increasing tendency of hydrolysis :

B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

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S r C l_{2} < B a C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

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B a C l_{2} < S r C l_{2} < C a C l_{2} < B e C l_{2} < M g C l_{2}

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B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2}

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Solution

The correct option is A $B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}$
The increasing tendency of hydrolysis of alkaline earth metal chlorides is $B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}$ . The covalent character and the amount of hydrolysis decreases from beryllium chloride to barium chloride. Thus only $B e C l_{2}$ and $M g C l_{2}$ get hydrolyzed due to their covalent nature. Other halides do not get hydrolyzed.

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