Arrange $F, C l, O, N$ in the decreasing order of electronegativity.

O > F > N > C l

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F > N > C l > O

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C l > F > N > O

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F > O > N \approx C l

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Solution

The correct option is D $F > O > N \approx C l$
Electronegativity(E.N) of elements are; $F = 4, C l = 3, N = 3, O = 3.5$ .
Therefore, the trend is : $F > O > N = C l$ .
This can be explained as, on moving from left to right across a period, the E.N increases and also on moving down a group from top to bottom the E.N decreases.

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Arrange F, Cl, O, and N in the decreasing order of electronegativity.

Q. Considering the elements F, Cl, O and N the correct order of their chemical reactivity in terms of oxidizing property is:
(a) F > Cl > O > N (b) F > O > Cl > N
(c) Cl > F > O > N (d) O > F > N > Cl

Considering the elements F, Cl, O and N, the correct order of their chemical reactivity in terms of oxidizing property is:
(a) F > Cl > O > N
(b) F > O > Cl > N
(c) Cl > F > O > N
(d) O > F > N > Cl

Arrange F, Cl, O, and N in the decreasing order of electronegativity.

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Arrange F,Cl,O,N in the decreasing order of electronegativity.

The correct option is D F>O>N≈ClElectronegativity(E.N) of elements are; F=4,Cl=3,N=3,O=3.5.Therefore, the trend is : F>O>N=Cl.This can be explained as, on moving from left to right across a period, the E.N increases and also on moving down a group from top to bottom the E.N decreases.

Arrange $F, C l, O, N$ in the decreasing order of electronegativity.