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Standard XII

Chemistry

Magnetic Properties

Arrange follo...

Question

Arrange following complex ions in increasing order of crystal field splittingenergy $Δ_{0})$ :

$[C r (C l)_{6}]^{3 -}, [C r (C N)_{6}]^{3 -}$ , $[C r (N H_{3})_{6}]^{3 +}$

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Solution

Among the ligands $C l^{-}, N H_{3}$ and $C N^{-}, C l^{-}$ has the lowest ligand field strength while $C N^{-}$ has the highest ligand field strength.
Moreover, the more is field strength of ligand the more will be its crystal field splitting energy.

Therefore, increasing order of crystal field splitting energies is:

$[C r (C l)_{6}]^{3 -} < [C r (N H_{3})_{6}]^{3 +} < [C r (C N)_{6}]^{3 -}$

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Similar questions

Arrange the following complex ions in increasing order of crystal field splitting energy $△_{0} .$
$[C r (C l)_{6}]^{3 -}, [C r (C N)_{6}]^{3 -}, [C r (N H_{3})_{6}]^{3 +}$

C r^{3 +}

form four complexes with four different ligands which are

[C r (C l)_{6}]^{3 -}, [C r (H_{2} O)_{6}]^{3 +}, [C r (N H_{3})_{6}]^{3 +}

and

[C r (C N)_{6}]^{3 -}

. The order of CFSE

(Δ_{o})

in these complexes is in the order :

Q. Arrange following complex ions in increasing order of crystal field splitting energy [Cr(Cl)6]3–, [Cr(CN)6]3–, [Cr(NH3)6]3+

The absorption maxima of some complexions are as follows:

$[C r C l_{6}]^{3 -} - 760 n m$

$[C r (N H_{3})_{6}]^{3 +} - 470 n m$

$[C r (H_{2} O)_{6}]^{3 +} - 695 n m$

The order of $Δ_{o}$ for these ions is

Q. Assertion :

Δ_{o}

increases in the order of

[C r C l_{6}]^{3 -} < [C r (C N)_{6}]^{3 -} < [C r (C_{2} O_{4})_{3}]^{3 -}

Reason: The stronger the ligand field, the higher will be

Δ_{o}

value.

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Magnetic Properties

Standard XII Chemistry

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Arrange following complex ions in increasing order of crystal field splittingenergy Δ0): [Cr(Cl)6]3−,[Cr(CN)6]3−, [Cr(NH3)6]3+

Arrange following complex ions in increasing order of crystal field splittingenergy $Δ_{0})$ :

$[C r (C l)_{6}]^{3 -}, [C r (C N)_{6}]^{3 -}$ , $[C r (N H_{3})_{6}]^{3 +}$