Arrange the following complex ions in increasing order of crystal field splitting energy $△_{0} .$
$[C r (C l)_{6}]^{3 -}, [C r (C N)_{6}]^{3 -}, [C r (N H_{3})_{6}]^{3 +}$

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Solution

CFSE is higher when the complex contains strong field ligand. Thus, crystal field splitting energy increases in the order

$[C r (C l)_{6}]^{3 -} < [C r (N H_{3})_{6}]^{3 +} < [C r (C N)_{6}]^{3 -}$

Because according to spectrochemical series the order of field strength is

$C l^{-} < N H_{3} < C N^{-}$

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C r^{3 +}

[C r (C l)_{6}]^{3 -}, [C r (H_{2} O)_{6}]^{3 +}, [C r (N H_{3})_{6}]^{3 +}

[C r (C N)_{6}]^{3 -}

(Δ_{o})

The absorption maxima of some complexions are as follows:

$[C r C l_{6}]^{3 -} - 760 n m$

$[C r (N H_{3})_{6}]^{3 +} - 470 n m$

$[C r (H_{2} O)_{6}]^{3 +} - 695 n m$

The order of $Δ_{o}$ for these ions is

Δ_{o}

[C r C l_{6}]^{3 -} < [C r (C N)_{6}]^{3 -} < [C r (C_{2} O_{4})_{3}]^{3 -}

Δ_{o}

The crystal field-splitting for $C r^{3 +}$ ion in octahedral field increases for ligands $I, H_{2} O, N H_{3}, C N^{-}$ and the order is :

[T i (N C S)_{6}]^{3 -}

(h = 6.626 \times 10^{- 34} J s; c = 3 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e)

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