Question

$\left[Ti\right(NCS{)}_6{]}^{3-}$ ion exhibits a single absorption band at 544 nm. What will be the crystal field splitting energy (in kJ/mol) of the complex ?$(h=6.626\times {10}^{-34}Js;c=3\times {10}^{8}m/s;N_A=6.02\times {10}^{23}ions/mole)$

• A. $240kJ/mol$
• B. $220kJ/mol$
• C. $270kJ/mol$
• D. $250kJ/mol$

Answer 1

The correct option is B $220kJ/mol$

The expression for the crystal field splitting energy is $=hv=\frac{hc}{\lambda }.$
Here, h is the Planck's constant, $v$ is the frequency of light, c and are the speed and the wavelengths of light respectively.
Substitute values in the above expression.
splitting energy = $\frac{6.626\times {10}^{-34}Js\times 3\times {10}^{8}m/s}{544\times {10}^9}=3.65\times {10}^{-19}$
Convert the crystal field splitting energy from J/ion to kJ/mol.
$=3.65\times {10}^{-19}\times 6.02\times {10}^{23}ions/mole=219.73kJmo{l}^{-1}$