Question

Arrange $\frac{2}{7},\frac{1}{7},\frac{4}{7}$ and $\frac{3}{7}$ in ascending order.

• A. $\frac{1}{7}<\frac{2}{7}<\frac{4}{7}<\frac{3}{7}$
• B. $\frac{1}{7}<\frac{2}{7}<\frac{3}{7}<\frac{4}{7}$
• C. $\frac{3}{7}<\frac{1}{7}<\frac{4}{7}<\frac{2}{7}$
• D. $\frac{4}{7}<\frac{2}{7}<\frac{3}{7}<\frac{1}{7}$

Answer 1

The correct option is B $\frac{1}{7}<\frac{2}{7}<\frac{3}{7}<\frac{4}{7}$

The given fractions have same denominators, so they are like fractions.
We know that, for like fractions, the higher the numerator, the higher the fraction.

Comparing the numerators of the given fraction, we have 1 < 2 < 3 < 4.

Hence, the ascending order of the fractions is $\frac{1}{7}<\frac{2}{7}<\frac{3}{7}<\frac{4}{7}$.