Arrange in the increasing order of nucleophilicity.
${C F}_{3} {C O}_{2}^{-}, {C I}_{3} {C O}_{2}^{-}, {C H}_{3} {C H}_{2} {C O}_{2}^{-}$

{C F}_{3} {C O}_{2}^{-} > {C I}_{3} {C O}_{2}^{-} < {C H}_{3} {C H}_{2} {C O}_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C F}_{3} {C O}_{2}^{-} < {C I}_{3} {C O}_{2}^{-} > {C H}_{3} {C H}_{2} {C O}_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C F}_{3} {C O}_{2}^{-} > {C I}_{3} {C O}_{2}^{-} > {C H}_{3} {C H}_{2} {C O}_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C F}_{3} {C O}_{2}^{-} < {C I}_{3} {C O}_{2}^{-} < {C H}_{3} {C H}_{2} {C O}_{2}^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D ${C F}_{3} {C O}_{2}^{-} < {C I}_{3} {C O}_{2}^{-} < {C H}_{3} {C H}_{2} {C O}_{2}^{-}$
In the polar aprotic solvent, the increasing order of nucleophilicity is ${C F}_{3} {C O}_{2}^{-} < {C I}_{3} {C O}_{2}^{-} < {C H}_{3} {C H}_{2} {C O}_{2}^{-}$ .
The decreasing order of electronegativity is $F > I$ . When trifluoromethyl (or triiodomethyl) group is present, the nucleophilicity decreases due to the electron withdrawing effect of trifluoromethyl (or triiodomthyl) group. The decrease is more pronounced in trifluoroacetate ion than in triiodoacetetate ion.

Suggest Corrections

Similar questions

C H_{3} - C H_{2} - C \equiv C^{-}

C H_{3} - C H_{2} - S^{-}

{C H_{3} - C H_{2} - C O_{2}}^{-}

C H_{3} - C H_{2} - O^{-}

{C F}_{3} {{C H}_{2} O}^{-}, {C H}_{3} {{C H}_{2} O}^{-}, {C F}_{3} {{C H}_{2} S}^{-}, {C H}_{3} {{C H}_{2} S}^{-}

{C H}_{3} - {C H}_{2} - {C O}_{2}^{⊖} {N a}^{\oplus} Δ - ------ \to N a O H / C a O Z

A, B

C

C O_{2}

C H_{3} C O C H O

Join BYJU'S Learning Program