Arrange the alkyl in decreasing order of their mass.

C H_{3} C l > H_{2} O > C H_{3} B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C l > C H_{3} B r > H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} B r > C H_{3} C l > H_{2} O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} O > C H_{3} C l > C H_{3} B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C H_{3} B r > C H_{3} C l > H_{2} O$
$C H_{3} B r$ Atomic mass $\Rightarrow$ $12 + 3 + 80 = 95$
$C H_{3} C l$ Atomic mass $\Rightarrow$ $12 + 3 + 35.5 = 50.5$
$H_{2} O$ Atomic mass $\Rightarrow$ $16 + 2 = 18$
According to given Atomic masses of compounds the decreasing order is $C H_{3} B r > C H_{3} C l > H_{2} O$ .

Suggest Corrections

Similar questions

Compare the dipole moment of the following.

CH₃F,CH₃Cl,CH₃Br, CH3 I.

C H_{3} C l, C H_{3} B r, C H_{3} I

C H_{3} F

{C H}_{3} O H

S_{N} 2

{C H}_{3} O H

{C H}_{3} F

{C H}_{3} C l

{C H}_{3} B r

{C H}_{3} I

{C H}_{3} O {S O}_{2} {C F}_{3}

^{14} {C H}_{3} O H

C H_{3} C l, C H_{3} B r, C H_{3} I, C H_{3} F

S_{N} 2

{C H}_{3} C l + I^{-} A c e t o n e - ---- \to

{C H}_{3} B r + I^{-} A c e t o n e - ---- \to

Join BYJU'S Learning Program