Arrange the carbanions, (CH3)3¯¯¯¯C,¯¯¯¯CCl3,(CH3)2¯¯¯¯CH,C6H5¯¯¯¯CH2 , in order of their decreasing stability:
A
C6H5¯¯¯¯CH2>¯¯¯¯CCl3>(CH3)3¯¯¯¯C>(CH3)2¯¯¯¯CH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(CH3)2¯¯¯¯CH>¯¯¯¯CCl3>C6H5¯¯¯¯CH2>(CH3)3¯¯¯¯C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
¯¯¯¯CCl3>C6H5¯¯¯¯CH2>(CH3)2¯¯¯¯CH>(CH3)3¯¯¯¯C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(CH3)3¯¯¯¯C>(CH3)2¯¯¯¯CH>C6H5¯¯¯¯CH2>¯¯¯¯CCl3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A¯¯¯¯CCl3>C6H5¯¯¯¯CH2>(CH3)2¯¯¯¯CH>(CH3)3¯¯¯¯C Due to the −I effect of three chlorine atoms and due to pπ−dπ bonding CCl−3 is extra stable. Carbanion follow stability order. ¯¯¯¯CCl3>C6H5¯¯¯¯CH2>(CH3)2¯¯¯¯CH>(CH3)3¯¯¯¯C
In C6H5CH−2 the −M effect delocalizes the -ve charge on carbon. The CH3 group in 1st and 3rd destabilizes the -ve charge on carbon.