Arrange the compounds in decreasing order of their dipole moment.

IV> III> I> II

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IV> I> III> II

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I> III> IV> II

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I> IV> III> II

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Solution

The correct option is C I> IV> III> II
More the charge separation more will be dipole moment and more $E N$ electronegativity difference, more will be dipole moment.
${C H}_{3} {C H}_{2} {N O}_{2} > {C H}_{3} {C H}_{2} C N > {C H}_{3} {C H}_{2} - F > {C H}_{3} {C H}_{2} - {N H}_{2}$

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