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Question

Arrange the following carbanions in decreasing order of stability.
874614_3bce56ee313146e9898bf2ea6d797c8e.png

A
IV>III>I>II
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B
IV>II>III>I
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C
IV>III>II>I
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D
III>IV>II>I
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Solution

The correct option is C IV>III>II>I
In IV, 3 withdrawing group, most unstable In III, II 2 withdrawing group but in II two CH3 (electron releasing group) present :. III more reactive or unstable then II
In I, only one electron-withdrawing group more stable than other
IV>III>II>I
Hence, (C) is correct

2004600_874614_ans_00876a621bb04624ad9f327206dcaec1.PNG

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