Arrange the following compound in increasing order of bond strength.

$C H_{3} - C H_{3}, C H_{2} = C H - C H_{3}, H C \equiv C - C H_{3}$

C H_{2} = C H - C H_{3}

H C \equiv C - C H_{3}

C H_{3} - C H_{3}

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H C \equiv C - C H_{3}

C H_{3} - C H_{3}

C H_{2} = C H - C H_{3}

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C H_{3} - C H_{3}

C H_{2} = C H - C H_{3}

H C \equiv C - C H_{3}

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C H_{2} = C H - C H_{3}

C H_{3} - C H_{3}

H C \equiv C - C H_{3}

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Solution

The correct option is A $C H_{3} - C H_{3}$ < $C H_{2} = C H - C H_{3}$ < $H C \equiv C - C H_{3}$
Bond strength:

$s p$ > $s p^{2}$ > $s p^{3}$

$C H_{3} - C H_{3}$ < $C H_{2} = C H - C H_{3}$ < $H C \equiv C - C H_{3}$

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Similar questions

H C \equiv C^{-}, {C H}_{3} C H = {C H}^{-}, {C H}_{3} {C H}_{2}^{-}

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

{C H}_{3} - C H = {C H}_{2}

{C H}_{3} - C H = C H - {C H}_{3}

{C H}_{3} - C_{3} = C H - {C H}_{3}

{C H}_{3} - {C H}_{3} | C = {C H}_{3} | C - {C H}_{3}

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

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