Arrange the following compounds in decreasing order of acidity - i HC - C H ii H 2 C - C H 2 iii H 3 C - C H 3

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Standard XII

Chemistry

Acidic Nature vs Percentage S Characters

Arrange the f...

Question

Arrange the following compounds in decreasing order of acidity -
(i) $H C \equiv C H$
(ii) $H_{2} C = C H_{2}$
(iii) $H_{3} C - C H_{3}$

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Solution

As more is the stability of conjugate base more is the acidic strength. Stability of conjugate base of given compounds
$H C \equiv C^{-} > H_{2} C = C H^{-} > H_{3} C - C H_{2}^{-}$
Therefore Acidic strength order :
$H C \equiv C H > H_{2} C = C H_{2} > H_{3} C - C H_{3}$

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Arrange the following compounds in decreasing order of acidity - (i) HC ≡ CH (ii) H2C = CH2 (iii) H3C − CH3

As more is the stability of conjugate base more is the acidic strength. Stability of conjugate base of given compounds HC≡C−>H2C=CH−>H3C−CH−2 Therefore Acidic strength order : HC≡CH>H2C=CH2>H3C−CH3

Arrange the following compounds in decreasing order of acidity -
(i) $H C \equiv C H$
(ii) $H_{2} C = C H_{2}$
(iii) $H_{3} C - C H_{3}$

As more is the stability of conjugate base more is the acidic strength. Stability of conjugate base of given compounds
$H C \equiv C^{-} > H_{2} C = C H^{-} > H_{3} C - C H_{2}^{-}$
Therefore Acidic strength order :
$H C \equiv C H > H_{2} C = C H_{2} > H_{3} C - C H_{3}$