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Hydrohalogenation of Alkenes

Arrange the f...

Question

Arrange the following compounds in decreasing order of reactivity with $B r_{2}$

$C H_{2} = C H_{2} (I), C H \equiv C H (I I), C H_{2} = C H C l (I I I)$

II > I as well as III

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I > II as well as III

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II is more reactive than III but less than I

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II is less reactive than III but more than I

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Solution

The correct option is C
II is more reactive than III but less than I

Stability of the carbocation formed follows the order

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Similar questions

Arrange the following compounds in decreasing order of reactivity with Br2

CH2=CH2 (I), CH ≡ CH (II), CH2=CHCl (III)

C H_{2} = C H - C_{6} H_{4} (N O_{2})

C H_{2} = C H - C_{6} H_{4} (C H_{3})

C H_{2} = C H - C_{6} H_{4} (O C H_{3})

C H_{2} = C H - C H = C H - + C H_{2}

C H_{2} = C H - + C H - C H = C H_{2}

C H_{2} = C H - + C H - - C H - + C H_{2}

+ C H_{2} - C H = C H - - C H - + C H_{2}

H C \equiv C H

H_{2} C = C H_{2}

H_{3} C - C H_{3}

C H \equiv C H

C H_{2} = C H_{2}

H_{2} C = C H - C l

H C | C l = C H | C l

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