Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.
I. $C H_{2} = C H - C_{6} H_{4} (N O_{2})$
II. $C H_{2} = C H - C_{6} H_{4} (C H_{3})$
III. $C H_{2} = C H - C_{6} H_{4} (O C H_{3})$

I > I I > I I I

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I I > I > I I

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I I I > I I > I

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I > I I I > I I

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Solution

The correct option is B $I I I > I I > I$
Electron releasing groups such as $- C H_{3}, - O C H_{3}$ activate the monomer towards cationic polymer as it stabilizes the carbocation formed. On the other hand, $- N O_{2}$ is an electron-withdrawing group. So, it reduces the stability of carbocation formed.

Thus, the correct order is:

$C H_{2} = C H - C_{6} H_{4} (O C H_{3}) > C H_{2} = C H - C_{6} H_{4} (C H_{3}) > C H_{2} = C H - C_{6} H_{4} (N O_{2})$ .

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Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.
I. $C H_{2} = C H - C_{6} H_{4} (N O_{2})$
II. $C H_{2} = C H - C_{6} H_{4} (C H_{3})$
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