Arrange the following compounds in decreasing order of their heats of combustion:

(iii) > (ii) > (i)

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(ii) > (i) > (iii)

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(iii) > (i) > (ii)

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(i) > (ii) > (iii)

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Solution

The correct option is D (i) > (ii) > (iii)
Heat of combustion is inversely proportional to stability.
Since three membered ring is most unstable due to angular strain so it is having highest heat of combustion.
So the order for heat of combustion is: $(i) > (i i) > (i i i)$

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