Question

Arrange the following compounds in descending order on the basis of number of carbon atoms present in them.
(A) Palmitic acid (B) Serine (C) Ribose (D) Arachidoric acid (E) Glucose

• A. D C A B E
• B. B C E A D
• C. D A E C B
• D. C B A D E

Answer 1

The correct option is C D A E C B

• Empirical formula of Palmitic acid is C${}_{16}$H${}_{32}$O${}_2$ ( 16 carbon atoms)
• Empirical formula of Serine is C${}_3$H${}_7$NO${}_3$( 3 Carbon atoms)
• Empirical formula of Ribose is C${}_5$H${}_{10}$O${}_5$( 5 Carbon atoms)
• Empirical formula of Arachidonic acid is C${}_{20}$H${}_{32}$O${}_2$ (20 Carbon atoms)
• The empirical formula of Glucose is C${}_6$H${}_{12}$O${}_6$ (6 Carbon atoms)

Thus, the order of these compounds on the basis of a number of carbon atoms in descending order would be Arachidonic acid, Palmitic acid, Glucose, Ribose, and Serine.

Thus, the correct answer is option C.