Question

Arrange the following compounds in order of their Molar conductance:
(I) $K\left[Co\right({NO}_2{)}_4\left({NH}_3{)}_2\right]$
(II) $\left[Cr\right(ONO{)}_3\left({NH}_3{)}_3\right]$
(III) $\left[Cr\right(N{H}_3{)}_6]{Cl}_3$
(IV) $Mg\left[Cr{\left({NO}_2\right)}_5\left({NH}_3\right)\right]$

• A. II < I < IV < III
• B. II < IV < I < III
• C. II < I = IV < III
• D. IV < III < II < I

Answer 1

The correct option is C II < I = IV < III

(I) Compounds will give $2$ ions during ionization.

(II) Will give no ion during ionization.

(III) Will give $4$ ions during ionization.

(IV) Will give $2$ ions during ionization.

Molar conductance $\propto$ Number of ions in the solution

So correct order will be Option C

$II<I=IV<III$