Question

Arrange the following fractions in ascending order.

$\frac{1}{12},\frac{1}{10},\frac{1}{19},\frac{1}{15}$

• A. $\frac{1}{19},\frac{1}{10},\frac{1}{12},\frac{1}{15}$
• B. $\frac{1}{10},\frac{1}{12},\frac{1}{19},\frac{1}{15}$
• C. $\frac{1}{19},\frac{1}{15},\frac{1}{12},\frac{1}{10}$
• D. $\frac{1}{12},\frac{1}{10},\frac{1}{19},\frac{1}{15}$

Answer 1

The correct option is C

$\frac{1}{19},\frac{1}{15},\frac{1}{12},\frac{1}{10}$

When two fractions have the same numerator, the one with the smaller denominator is the larger fraction of the two.

Comparing the denominators, we have 19 > 15 > 12 > 10.

$\therefore \frac{1}{19}<\frac{1}{15}<\frac{1}{12}<\frac{1}{10}$