Arrange the following groups
$- F, - O H, - N H_{2}$ in the increasing order of their $- I$ effect.

- N H_{2} < - F < - O H

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- N H_{2} < - O H < - F

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- O H < - F < - N H_{2}

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- F < - N H_{2} < - O H

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Solution

The correct option is B $- N H_{2} < - O H < - F$
$- I$ effect depends on the electronegativity of the element .
More the electronegativity, more is the electron withdrawing power and more is the $- I$ effect shown by that particular group.
Here, fluorine, oxygen and nitrogen are of same period.
Along the period , when we move from left to right, the electronegativity generally increases.
Electronegativity follows the order
Nitrogen<Oxygen<Fluorine
So the $- I$ effect will follow the same order i.e.
$- N H_{2} < - O H < - F$

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