Arrange the following groups in order of decreasing -R (or -M) power.
1) $N O_{2}$ 2) $S O_{3} H$ 3) $C F_{3}$ 4) $C H O$

1 > 3 > 2 > 4

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1 > 2 > 3 > 4

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1 > 4 > 3> 2

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4 > 3> 2 > 1

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Solution

The correct option is C 1 > 3 > 2 > 4
-R has the tendency to take the Pi electrons away
from the group. Thus,
-R order :- $N O_{2} > C F_{3} > S O_{3} H > C H O$

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(1) $- C \equiv N$ , (2) $- C O N H_{2}$ , (3) $- O | | C -$ , (4) $- C H O$
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Arrange the following groups in order of decreasing -R (or -M) power.1)NO2 2) SO3H 3)CF3 4) CHO

The correct option is C 1 > 3 > 2 > 4-R has the tendency to take the Pi electrons awayfrom the group. Thus,-R order :- NO2>CF3>SO3H>CHO

Arrange the following groups in order of decreasing -R (or -M) power.
1) $N O_{2}$ 2) $S O_{3} H$ 3) $C F_{3}$ 4) $C H O$

The correct option is C 1 > 3 > 2 > 4
-R has the tendency to take the Pi electrons away
from the group. Thus,
-R order :- $N O_{2} > C F_{3} > S O_{3} H > C H O$