Arrange the following hydrides in their increasing acid strength $[C H_{4}, H_{2} S, P H_{3}$ and $S i H_{4}]$ :

H_{2} S < P H_{3} < S i H_{4} < C H_{4}

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C H_{4} < S i H_{4} < P H_{3} < H_{2} S

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S i H_{4} < C H_{4} < P H_{3} < H_{2} S

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C H_{4} < H_{2} S < P H_{3} < S i H_{4}

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Solution

The correct option is B $C H_{4} < S i H_{4} < P H_{3} < H_{2} S$
The increasing order of the acid strength is $C H_{4} < S i H_{4} < P H_{3} < H_{2} S$
In a period, the nature of hydrides changes from basic to acidic. Hence, the increasing order of acid strength is $S i H_{4} < P H_{3} < H_{2} S$ .
In a group, the acidic nature of hydrides increases.
Hence, $S i H_{4}$ is more acidic than $C H_{4}$

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