Question

Arrange the following in an ascending order:

$\mathrm{5.33...},\mathrm{8.010010001...},7.3175,2+\sqrt{3},\frac{9}{2}$.

• A. $\frac{9}{2},2+\sqrt{3},\mathrm{5.33...},7.3175,\mathrm{8.010010001...}$
• B. $2+\sqrt{3},\frac{9}{2},7.3175,\mathrm{5.33...},\mathrm{8.010010001...}$
• C. $2+\sqrt{3},\frac{9}{2},\mathrm{5.33...},7.3175,\mathrm{8.010010001...}$
• D. $\frac{9}{2},\mathrm{5.33...},7.3175,2+\sqrt{3},\mathrm{8.010010001...}$

Answer 1

Answer: (C)

$2+\sqrt{3},\frac{9}{2},\mathrm{5.33...},7.3175,\mathrm{8.010010001...}$

Given, $\mathrm{5.33...},\mathrm{8.010010001...},7.3175,2+\sqrt{3},\frac{9}{2}$.

Now, $2+\sqrt{3}=3.732$ and $\frac{9}{2}=4.5$.

Arranging in ascending order, we get,

$2+\sqrt{3},\frac{9}{2},\mathrm{5.33...},7.3175,8.010010001,...$

Hence, option $C$ is correct.