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Question

The solution set of x2>0,x9<0 and x290 is

A
[3,9]
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B
[3,9)
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C
(3,9]
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D
(3,9)
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Solution

The correct option is B [3,9)
x2>0x>2 (1)x9<0x<9 (2)x290(x+3)(x3)0x(,3][3,) (3)
From (1),(2) and (3),
x[3,9)

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