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Method of Intervals

Solution set ...

Question

Solution set of $x (2^{x} - 1) (3^{x} - 9) (x - 3) < 0$ is

A

(2, 3)

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B

(- \infty, 0) \cup (2, 3)

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C

(- \infty, 2) \cup (3, \infty)

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D

(- \infty, 0] \cup [3, \infty)

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Solution

The correct option is A $(2, 3)$
Critical points are $0, 2$ and $3.$
Here, critical point $0$ has even $(2)$ powers. That’s why sign doesn’t change at $x = 0.$
$∴ x \in (2, 3)$

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Method of Intervals

Standard XII Mathematics

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