Question

Arrange the following in ascending order:
$\frac{5}{8},\frac{5}{6},\frac{1}{2}$

• A. $\frac{1}{2},\frac{5}{8},\frac{5}{6}$
• B. $\frac{5}{6},\frac{5}{8},\frac{1}{2}$
• C. $\frac{5}{8},\frac{1}{2},\frac{5}{6}$
• D. $\frac{1}{2},\frac{5}{6},\frac{5}{8}$

Answer 1

The correct option is A $\frac{1}{2},\frac{5}{8},\frac{5}{6}$

Given fractions are : $\frac{5}{8},\frac{5}{6},\frac{1}{2}$

LCM of $8,6,2$ is $24$

So,

$\frac{5}{8}\times \frac{3}{3}$ = $\frac{15}{24}$

$\frac{5}{6}\times \frac{4}{4}$ = $\frac{20}{24}$

$\frac{1}{2}\times \frac{12}{12}$ = $\frac{12}{24}$

As we know, $12<15<20$

So,

$\frac{1}{2}<\frac{5}{8}<\frac{5}{6}$