Question

Arrange the following in ascending order of their values from top to bottom.

• A. $2^0+3^0+4^0$
• B. $(2+3+4{)}^0$
• C. $4^1$
• D. $3^1-2^0$

Answer 1

$\text{We know that}{x}^0=1\text{and}{x}^1=x.$

• $2^0+3^0+4^0=1+1+1=3$
• $4^1=4$
• $3^1-2^0=3-1=2$
• $(2+3+4{)}^0=9^0=1$

Clearly, 1 < 2 < 3 < 4
So, increasing order will be
$(2+3+4{)}^0$
$3^1-2^0$
$2^0+3^0+4^0$
$4^1$