Arrange the following in decreasing order of their basic strength:
$C_{6} H_{5} N H_{2}, C_{2} H_{5} N H_{2},$
$(C_{2} H_{5})_{2} N H, N H_{3}$

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Solution

Basicity of amines

Ammonia is more basic than aniline as in aniline, the lone pair of electrons on $N$ atom is in resonance with benzene ring so it is not available for the donation.

Ethyl amine is more basic than ammonia because in ethyl amine, the $+ I$ effect of ethyl group increases the electron density on $N$ atom so it can donate electrons easily while diethylamine is most basic due to $+ I$ effect of two ethyl groups.

Hence, the decreasing order of basic strength of the above amines and ammonia follows the following order:

$(C_{2} H_{5})_{2} N H > C_{2} H_{5} N H_{2} > N H_{3} > C_{6} H_{5} N H_{2}$

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Similar questions

A)

C_{2} H_{5} N H_{2}, C_{6} H_{5} N H_{2}, N H_{3},

C_{6} H_{5} C H_{2} N H_{2} & (C_{2} H_{5})_{2} N H

B)

C_{2} H_{5} N H_{2}, (C_{2} H_{5})_{2} N H,

(C_{2} H_{5})_{3} N, C_{6} H_{5} N H_{2}

C)

C H_{3} N H_{2}, (C H_{3})_{2} N H, (C H_{3})_{3} N,

C_{6} H_{5} N H_{2}, C_{6} H_{5} C H_{2} N H_{2}

C_{6} H_{5} N H_{2}, C_{2} H_{5} N H_{2}, (C_{2} H_{5})_{2} N H, N H_{3}

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