Arrange the following in the correct order of stability:

I > I I > I I I > I V

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I > I I > I V > I I I

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I I > I > I V > I I I

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I > I V > I I > I I I

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Solution

The correct option is B $I > I I > I V > I I I$
At metaposition, hyperconjugation do not take place.
Inductive effect order $- H < - D$ i.e $R - C H_{3} < R - C D_{3}$ (Stability)
Hyperconjugation order $- H < - D$ i.e $R - C H_{3} > R - C D_{3}$ (Stability)
and Hyperconjugated compound is always more stable than inductive effect.
Therefore, Order is $I > I I > I V > I I I$

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K_{2} C O_{3} (I), M g C O_{3} (I I), C a C O_{3} (I I I), B e C O_{3} (I V)

Arrange the following carbocations in decreasing order of stability

The stability of carbanions in the following

i) $R C \equiv ⊖ C$

ii)

iii) $R_{2} C = ⊖ C H$

iv) $R_{3} C - ⊖ C H_{2}$

is in the order of

H_{2} S O_{4}

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