Arrange the following in the descending order of their resultant magnetic moments considering two magnets of same moment :
a) They are kept one upon the other with like poles in contact
b) They are kept one upon the other with unlike poles in contact
c) They are arranged in perpendicular directions
d) They are inclined $60^{o}$ with like poles in contact

a, c, d, b

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a, b, c, d

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a, d, c, b

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d, b, c, a

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Solution

The correct option is A a, d, c, b
$N L S$
$M_{a} = (P_{1} + P)_{2} L$
$M_{1} = (P_{2} + P)_{1} L$
$M_{e} = (\sqrt{4^{2} + 1_{2}^{2}}) L$
$M d = (\sqrt{P_{1}^{2}} + P_{2}^{2} + K P_{1} P_{2} \times \frac{1}{2})$
$= \sqrt{P_{1}^{2} + P_{2}^{2} + P_{1} P_{2}}$
$m a > m d > m c > m r$

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The correct option is A a, d, c, bNLSMa=(P1+P)2LM1=(P2+P)1LMe=(√42+122)LMd=(√P21+P22+KP1P2×12)=√P21+P22+P1P2ma>md>mc>mr

The correct option is A a, d, c, b
$N L S$
$M_{a} = (P_{1} + P)_{2} L$
$M_{1} = (P_{2} + P)_{1} L$
$M_{e} = (\sqrt{4^{2} + 1_{2}^{2}}) L$
$M d = (\sqrt{P_{1}^{2}} + P_{2}^{2} + K P_{1} P_{2} \times \frac{1}{2})$
$= \sqrt{P_{1}^{2} + P_{2}^{2} + P_{1} P_{2}}$
$m a > m d > m c > m r$