Arrange the following in the order of increasing oxidation number of chlorine: $C l_{2} O_{7}, C l_{2} O, H C l, C l F_{3}, C l_{2}$ .

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Solution

The order of increasing oxidation number of chlorine for $C l_{2} O_{7}, C l_{2} O, H C l, C l F_{3}, C l_{2}$ is $H C l (- 1), C l_{2} (0), C l_{2} O (+ 1), C l F_{3} (+ 3), C l_{2} O_{7} (+ 7)$ .
The numbers in bracket represents the oxidation number of chlorine. With increase in the number of electronegative F or O atoms, the oxidation number of chlorine increases.
The oxidation numbers of H, O and F are $+ 1$ , $- 2$ and $- 1$ respectively.

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