Arrange the following in their decreasing order of basic character.

I I I > I V > I > I I

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I > I I > I I I > I V

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I V > I I I > I I > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I > I I I > I > I V

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Solution

The correct option is A $I I I > I V > I > I I$
Electron donor species increase the basicity while electron withdrawing species reduces it.
(III) is the most basic due to +I effect of two $M e$ Groups. (II) is least basic since lone pair of $N$ is involved in resonance with two carbonyl groups.
Hence the order is:
$I I I > I V > I > I I$

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