Arrange the following ions I order of decreasing ionic radii: ${L i}^{2 +}$ ${H e}^{+}$ ${B e}^{3 +}$ .

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Solution

Among isoelectronic species, radius of cation decreases with increase in no . of positive charge.
So, the correct order of ionic radii will be:
$H e^{+} > L i^{2 +} > B e^{3 +}$

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Correct order of radius of the $1^{s t}$ orbit of $H$ , $H e^{+}, L i^{2 +}, B e^{3 +}$ is:

H, H e^{+}, L i^{2 +}, B e^{3 +}

H < H e^{+} < L i^{2 +} < B e^{3 +}

H e^{+}, L i^{2 +}

B e^{3 +}

1

H, {H e}^{+}, {L i}^{2 +}

{B e}^{3 +}

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