Question

Arrange the following orbitals of $H-$atom in the increasing order of their energy. $3p_x,2s,4d_{xy},3s,4p_z,3p_y,4s$

• A. $2s<3s=3p_x=3p_y<4s=4p_z=4d_{xy}$
• B. $2s<3s<3p_x=3p_y>4s=4p_z=4d_{xy}$
• C. $2s>3s<3p_x=3p_y<4s=4p_z=4d_{xy}$
• D. $2s<3s<3p_x=3p_y<4s<4p_z<4d_{xy}$

Answer 1

The correct option is A $2s<3s=3p_x=3p_y<4s=4p_z=4d_{xy}$

For single electron or $H$-atom energy of orbital is decided only by principle quantum number ($n$) i.e number of shell orbitals present in the same number of shell will here equal energy. Therefore, the correct answer is option $A$.

$2s<3s=3p_x=3p_y<4s=4p_z=4d_{xy}$